Question

Two masses 50 kg and 100 kg are separated by a distance of 10 m. What is the gravitational force of attraction between them?

$G=6.67\times {10}^{-11}N{m}^2/k{g}^2$

Answer 1

Step 1: Given:

$$\begin{gathered} {\mathrm{m}}_1=50\mathrm{kg} \\ {\mathrm{m}}_2=100\mathrm{kg} \\ \mathrm{d}=10\mathrm{m} \end{gathered}$$

Step 2: Calculating the gravitational force,

According to the universal law of gravitation “Everybody attracts every other body exerting a force which is directly proportional to the masses of two bodies and inversely proportional to the square of the distance between them”.

$F=\frac{G{m}_1{m}_2}{d^2}$

The value of the gravitational constant is specified and given as:

Substituting the values into the formula,

$F=\frac{6.67\times {10}^{-11}\times 50\times 100}{{10}^2}$

$=3.33\times {10}^{-9}\mathrm{N}$

Thus, the value of force between given masses is $3.33\times {10}^{-9}\mathrm{N}$.