1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Two masses M1=5kg and M2=10kg are connected at the ends of an inextensible string passing over a frictionless pulley as shown. When the masses are released, then the acceleration of the masses will be:

A
g
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
g/2
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
g/3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
g/4
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is C g/3Let the acceleration of the blocks and the tension in the string be a and T respectively.For block of mass M1 : M1a=T−M1g .........(1)For block of mass M2 : M2a=M2g−T .........(2)Adding (1) and (2) we get (M1+M2)a=(M2−M1)g⟹ a=M2−M1M2+M1gGiven : M1=5kg M2=10kg a=10−510+5g ⟹a=g3

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Expression for SHM
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program