Two masses m and 2m are joined to each other by means of a frictionless pulley as shown below. When the mass 2m is released, the mass m will ascend with an acceleration of

$\frac{g}{3}$

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$\frac{g}{2}$

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$g$

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$2 g$

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Solution

The correct option is A
$\frac{g}{3}$

From the second law of motion,
$2 m g - T = 2 m a . . . . . . . . (1)$
$T - m g = m a . . . . . . . . (2)$
Adding equations (1) and (2), $m g = 3 m a \Rightarrow a = \frac{g}{3}$
Hence, the correct choice is (a).

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The correct option is A g3 From the second law of motion, 2mg−T=2ma........(1) T−mg=ma........(2) Adding equations (1) and (2), mg=3ma⇒a=g3 Hence, the correct choice is (a).

The correct option is A
$\frac{g}{3}$

From the second law of motion,
$2 m g - T = 2 m a . . . . . . . . (1)$
$T - m g = m a . . . . . . . . (2)$
Adding equations (1) and (2), $m g = 3 m a \Rightarrow a = \frac{g}{3}$
Hence, the correct choice is (a).