Question

Two masses of 4kg and 5kg are connected by a string passing through a friction less pulley and are kept on a friction less table as shown in figure .The acceleration of 5kg mass is:

Answer 1

Given,

$Masses=M_1=4kg,M_2=5kg$

So,

$a=\frac{M_{1}g}{M_{!}+M_2}$

$a=\frac{5\times 9.8}{4+5}=\frac{49}{9}$

$=5.44m/s^2$

Thus, the acceleration of 5kg mass is $5.44m/s^2$