Two milk containers contains 398 l and 436 l of milk. The milk is to be
transferred to another container with the help of a drum. While transferring
to another container 7l and 11l of milk is left in both the containers
respectively. What will be the maximum capacity of the drum.

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Solution

Dear Student

volume V1 = 398 liters

V2 = 436 Litres

a drum of capacity D litres is used to transfer the milk to other containers. When we transfer milk, we transfer D litres, 2D litres, 3 D , 4D etc. amounts. If there is any milk left out, that will be a fraction of the capacity of the drum.

let m and n be integers.

V1 = 398 = m * D + 7 => m * D = 391 = 17 * 23

V2 = 436 = n * D + 11 => n * D = 425 = 5 * 5 * 17

Looking at both equations above, D = 17 , as only 17 occurs in both.

answer is 17 liters.

Regards

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Two milk containers contains 398 l and 436 l of milk. The milk is to be transferred to another container with the help of a drum. While transferring to another container 7l and 11l of milk is left in both the containers respectively. What will be the maximum capacity of the drum.

Two milk containers contains 398 l and 436 l of milk. The milk is to be
transferred to another container with the help of a drum. While transferring
to another container 7l and 11l of milk is left in both the containers
respectively. What will be the maximum capacity of the drum.