Two miscible liquids of densities $1.2 gm/cc$ and $1.4 gm/cc$ are mixed with a proportion ratio of their
volumes equal to $3 : 5$ . Then, the density of the resulting liquid in $gm/cc$ upto two decimals will be

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Solution

Let, the volume of first liquid be $V_{1} = 3 V$ Volume of second liquid $V_{2} = 5 V$
Given:
$ρ_{1} = 1.2 \frac{gm}{{cm}^{3}}$ ;
$ρ_{2} = 1.4 \frac{gm}{{cm}^{3}}$
Mass of first liquid :- $m_{1} = ρ_{1} v_{1} = 3.6 V$
Mass of second liquid :- $m_{2} = ρ_{2} v_{2} = 7 V$
So, Density of resulting liquid :-
$ρ_{mixture} = \frac{m_{total}}{V_{total}} = \frac{m_{1} + m_{2}}{v_{1} + v_{2}}$
$= \frac{3.6 V + 7 V}{3 V + 5 V} = \frac{10.6 V}{8 V} = 1.325$

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Two miscible liquids of densities 1.2 gm/cc and 1.4 gm/cc are mixed with a proportion ratio of their volumes equal to 3:5. Then, the density of the resulting liquid in gm/cc upto two decimals will be

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Two miscible liquids of densities $1.2 gm/cc$ and $1.4 gm/cc$ are mixed with a proportion ratio of their
volumes equal to $3 : 5$ . Then, the density of the resulting liquid in $gm/cc$ upto two decimals will be