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Question

Two moles of ammonia is introduced in a evacuated 500 mL vessel at high temperature. This decomposition reaction is?
2NH3(g)N2(g)+3H2(g)
At the equilibrium NH3 becomes 1 mole then the Kc would be:

A
0.42
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B
6.75
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C
1.7
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D
1.5
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Solution

The correct option is C 1.7
2NH3(g)N2(g)+3H2(g)atequil.22xx3x
Amount of NH3 left is 1 mole
22x=1
x=0.5
Kc=[N2][H2]3[NH3]
=(0.5)(1.5)31=1.7

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