Two moles of an ideal gas are allowed to expand from a volume of 10dm3to2m3 at 300 K against a pressure of 101.325 kPa. Calculate the work done.
A
-201.6 kJ
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B
13.22 kJ
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C
-810.6 J
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D
-18.96 kJ
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Solution
The correct option is A -201.6 kJ Given: V1=10dm3=0.01m3V2=2m3P=101.325kPa work done at constant pressure=−PdV=−101.325(2−0.01)=−101.325(1.99)=−201.636kJ