CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

Two moles of ideal monoatomic gas are allowed to expand adiabatically and reversibly from 300 K and 200 K. The work done in the system is:

(Cv=12.5 J/K/mole)

A
12.5 kJ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2.5 kJ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
625 kJ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
500 kJ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2.5 kJ
For an adiabatic process-

ΔE=q+W

As q=0,

ΔT =200300 =100

So the Work done =nCvΔT=2×12.5×(100)=2500J

W = 2.5kJ

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Thermodynamic Processes
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon