Question

Two moles of methane is mixed with 1 mole of oxygen gas then the density of the gas at ${27}^{o}C$ if the total pressure exerted by the gas is mixture is 3 atm will be: (Take $R=\frac{1}{12}$ Litre atm/mol/K)

Answer 1

$\text{Net Molecular Mass =}\frac{2\times (12+4)+1\left(32\right)}{3}=\frac{64}{3}PV=\frac{m}{M}RT=\frac{d}{M}RTPM=dRT\left(3\right)\left(\frac{64}{3}\right)=d\left(\frac{1}{12}\right)\left(300K\right)\Rightarrow d=\frac{64\times 12}{300}=2.56g/L$