Two mutually perpendicular forces are acting on an object. One of the forces acts in the direction of motion and the other is perpendicular to the direction of motion. During this interval, the kinetic energy of the body changes from 75 J to 100 J. The work done by the force acting perpendicular to the direction of the motion is:

75 J

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25 J

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100 J

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0 J

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Solution

The correct option is D $0 J$
Work done $W = F o r c e \times D i s p l a c e m e n t$
In the above question, the kinetic energy would increase only due to the force acting in the direction of motion. The force acting perpendicular to the direction of motion produces no displacement and so the work done by this force is zero.

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