When forces $F_{1}, F_{2}, F_{3}$ are acting on a particle of mass m such that $F_{2} a n d F_{3}$ are mutually perpendicular, then the particle remains stationary. If the force $F_{1}$ is now removed then the acceleration of the particle is

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Two Nucleons are at a separation of 1 fermi. Proton have a charge 1.6×10−19 C, the nuclear force between them is F1 both are neutrons, F2 if both are protons, F3 if one neutron and one proton then

The correct option is C F1 = F2 = F3Nuclear force is independent of charge of the nucleons.Thus nuclear force is same for any pair of two nucleons which are at same distance apart.∴F1=F2=F3

Two Nucleons are at a separation of $1$ fermi. Proton have a charge $1.6 \times 10^{- 19}$ $C$ , the nuclear force between them is $F_{1}$ both are neutrons, $F_{2}$ if both are protons, $F_{3}$ if one neutron and one proton then

The correct option is C $F_{1}$ = $F_{2}$ = $F_{3}$
Nuclear force is independent of charge of the nucleons.
Thus nuclear force is same for any pair of two nucleons which are at same distance apart.
$∴ F_{1} = F_{2} = F_{3}$