Question

Two numbers are respectively 20 percent and 50 percent more than a third number. What percent is the second of the first ?

Answer 1

Let the third number = x
$\therefore$ First number = $x+\frac{20}{100}x$
= $\frac{100x+20x}{100}=\frac{120x}{100}$
Second number = $x+\frac{50}{100}x$
= $\frac{100x+50x}{100}=\frac{150x}{100}$
Required % =$\frac{\frac{150x}{100}}{\frac{120x}{100}}$
= $\frac{150x}{100}\times \frac{100}{120x}\times 100$ = $\frac{150\times 100}{120}$
= $\frac{1500}{12}$= 125%