Question

Two numbers are such that $60$ of one is equal to $40$ of the other and sum of the numbers $320$. Find the larger number.

Answer 1

Give $x+y=320$...(1)

60% of x=40 % of y

$\frac{60x}{100}=\frac{40y}{100}$

$y=\frac{3}{2}x$

now from eq. (1)

$x+y=320$

$x+\frac{3x}{2}=320$

$5x=320\times 2$

$[x=128]$

and $y=3\times \frac{128}{2}=192$

Hence greater number is $[y=192]$.