Two object $A$ and $B$ are walking with speed $6 k m / h$ and $10 k m / h$ respectively in the same direction. Find the relative displacement of $B$ w.r.t $A$ after $4$ hours.

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Solution

For relative displacement we may calculate the relative velocity first for A with respect to $B$ as $V_{B A} = V_{B} - V_{A} = 10 - 6 = 4 k m / h$
So the relative displacement of B wrt A is $V_{B A} \times t = 4 \times 4 = 16 K m$

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Two object A and B are walking with speed 6 km/h and 10 km/h respectively in the same direction. Find the relative displacement of B w.r.t A after 4 hours.

For relative displacement we may calculate the relative velocity first for A with respect to B as VBA=VB−VA=10−6=4km/hSo the relative displacement of B wrt A is VBA×t=4×4=16Km

Two object $A$ and $B$ are walking with speed $6 k m / h$ and $10 k m / h$ respectively in the same direction. Find the relative displacement of $B$ w.r.t $A$ after $4$ hours.

For relative displacement we may calculate the relative velocity first for A with respect to $B$ as $V_{B A} = V_{B} - V_{A} = 10 - 6 = 4 k m / h$
So the relative displacement of B wrt A is $V_{B A} \times t = 4 \times 4 = 16 K m$