Question

Two objects of masses 100 kg and 200 kg are placed at a distance of 10 meters from each other. Calculate the gravitational force between them.$\left(G=6.67\times {10}^{-11}N{m}^2/k{g}^2\right)$

Answer 1

Step 1: Given data and drawing the diagram

Given data:

Here we have,

mass of one body $\left(m_1\right)$= 100 kg,

mass of the second body $\left(m_2\right)$= 200 kg,

Distance between the two bodies (d)= 10 meters,

Gravitational force is to be calculated (F)=?

Drawing the diagram of the situation:

Step 2: Formula used

We know that the gravitational force between two bodies is given by,

$F=\frac{G{m}_1{m}_2}{d^2}.........\left(a\right)$

where G = universal gravitational constant and its value is.$\left(G=6.67\times {10}^{-11}N{m}^2/k{g}^2\right)$.

Step 3: Calculating the force

On, putting all the given values in equation (a), we get

$F=\frac{6.67\times {10}^{-11}\times 100\times 200}{{10}^2}=13.34\times {10}^{-9}N.$

Hence, when two objects of masses 10kg and 20 kg are placed at a distance of 10 meters from each other will attract each other by the force of $13.34\times {10}^{-9}N.$