Two objects of masses 100g and 200g are moving along the line and direction with velocities of 2m s^-1 and 1m s^-1 respectively ,They collide and after the collosion, the first object moves at a velocity of 1.67 m s^-1. Determine the velocity of the secong object

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Solution

Here m =100g = 0.1kg
m' = 200g = 0.2kg
u = 2m/s and u' = 1m/s
v = 1.67m/s
According to the law of conservation of momentum:
Total momentum before collision = Total momentum after collision
mu + m'u' = mv + m'v'
0.1x2 + 0.2x1 = 0.1x1.67 + 0.2xv'
0.2+0.2=0.167+0.2v'
thus, we get
v'=1.165 m/s

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Two objects of masses 100g and 200g are moving along the line and direction with velocities of 2m s-1 and 1m s-1 respectively ,They collide and after the collosion, the first object moves at a velocity of 1.67 m s-1. Determine the velocity of the secong object

Here m =100g = 0.1kgm' = 200g = 0.2kgu = 2m/s and u' = 1m/sv = 1.67m/sAccording to the law of conservation of momentum:Total momentum before collision = Total momentum after collisionmu + m'u' = mv + m'v'0.1x2 + 0.2x1 = 0.1x1.67 + 0.2xv'0.2+0.2=0.167+0.2v'thus, we getv'=1.165 m/s

Two objects of masses 100g and 200g are moving along the line and direction with velocities of 2m s^-1 and 1m s^-1 respectively ,They collide and after the collosion, the first object moves at a velocity of 1.67 m s^-1. Determine the velocity of the secong object

Here m =100g = 0.1kg
m' = 200g = 0.2kg
u = 2m/s and u' = 1m/s
v = 1.67m/s
According to the law of conservation of momentum:
Total momentum before collision = Total momentum after collision
mu + m'u' = mv + m'v'
0.1x2 + 0.2x1 = 0.1x1.67 + 0.2xv'
0.2+0.2=0.167+0.2v'
thus, we get
v'=1.165 m/s