Two objects that are moving along an xy-plane on a frictionless floor collide. Assume that they form a closed, isolated system. The following table gives some of the momentum components (in kilogram meters per second) before and after the collision. Find the missing values (A, B):
Before collisionAfter collisionObjectPx∣PyPx∣PyA−4∣ 53 ∣ABB ∣−24∣2
(1, 11)
As explained vividly in the videos,
"The Linear momentum of a system remains constant in magnitude and direction, if the external forces acting on the system add up to zero.”
Utilizing the principle of law of conservation of linear momentum as there is no net External force on mentioned objects,
→Pl=→Pf
→(Px)i=(Px)ialso(Py)i=(Py)i
-4 + b = 3 + 4 5 - 2 = a + 2
b = 11 a = 1
(1,11) is the correct option.