Question

Two parallel and opposite forces,each 4000 N , are applied tangentially to the lower and upper faces of a cubical metal block 25cm on a side. Find the angle of shear and the displacement of the upper surface relative to the lower surface. Shear modulus of the metal is 8*10¹⁰N/m².

Answer 1

Dear student,
Find the answer to your query as under:

$$\begin{gathered} here, \\ F\hspace{0.17em}=4000N; \\ L\hspace{0.17em}=0.25m \\ A\hspace{0.17em}=0.0625m^2 \\ G=8\times {10}^{8}N{m}^{-2} \\ Now, \\ angleofshearstrain=\theta =\frac{F}{AG}=\frac{4000}{0.0625\times 8\times {10}^{10}}=8\times {10}^{-7}radians \\ now, \\ \theta =\frac{∆L}{L} \\ ∆L=L\times \theta \\ ∆L=8\times {10}^{-7}\times 0.25=2\times {10}^{-7}m. \end{gathered}$$

Regards
Satyendra Singh