Two parallel sides of a tranpezium are of lengths $27 c m$ and $19 c m$ respectively and the distance between them is $14 c m$ . Find the area of the trapezium.

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Solution

Here parallel sides are $a = 27$ cm and $b = 19$ cm and height is $h = 14$ cm

Area of trapezium $= \frac{1}{2} (a + b) \times h$

$= \frac{1}{2} \times (27 + 19) \times 14$

$= 46 \times 7 = 322$ sq.cm

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Two parallel sides of a tranpezium are of lengths 27cm and 19cm respectively and the distance between them is 14cm. Find the area of the trapezium.

Here parallel sides are a=27cm and b=19cm and height is h=14cmArea of trapezium=12(a+b)×h=12×(27+19)×14=46×7=322sq.cm

Two parallel sides of a tranpezium are of lengths $27 c m$ and $19 c m$ respectively and the distance between them is $14 c m$ . Find the area of the trapezium.

Here parallel sides are $a = 27$ cm and $b = 19$ cm and height is $h = 14$ cm

Area of trapezium $= \frac{1}{2} (a + b) \times h$

$= \frac{1}{2} \times (27 + 19) \times 14$

$= 46 \times 7 = 322$ sq.cm