The correct option is A Plate 1 of the capacitor acquires a positive charge and plate 2 an equal negative charge
As the rod CD moves to the right, from Fleming’s left hand rule, the free electrons in CD experience a force from C to D. Hence, the electrons move from C to D and, as a result, end C acquires a positive charge (due to loss of electrons) and end D acquires an equal negative charge (due to gain of electrons). Therefore, plate 1 acquires a positive charge and plate 2 acquires an equal negative charge.