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Question

# Two particle executes S.H.M. of same amplitude and frequency along the same straight line. They pass one another when going in opposite directions, each time their displacement is half of their amplitude. The phase difference between them is :-

A
30o
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B
60o
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C
90o
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D
120o
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Solution

## The correct option is C 120oy=a∼(ωt+ϕ0). According to the questiony=a2⇒a2=asin(ωt+ϕ0)⇒(ωt+ϕ0)=ϕ=π6 or 5π6Physical meaning of ϕ=π6 : Particle is at point P and it is going towards BSo phase difference △ϕ=5π6−π6=2π3=120o

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