1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Two particles execute S.H.M. of same amplitude and frequency along the same straight line. They pass one another when going in opposite directions. Each time their displacement is half of their amplitude. The phase difference between them is

A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D Let two simple harmonic motions are y=Asin ωt and y′=Asin(ωt+φ) In the first case A2=Asinωt⇒sinωt=12 ∴cosωt=√32 In the second case A2=Asin(ωt+φ) ⇒12=[sinωt.cosφ+cosωtsinφ]⇒12=[12cosφ+√32sinφ] ⇒1−cosφ=√3sinφ⇒(1−cosφ)2=3sin2φ⇒(1−cosφ)2=3(1−cos2φ) By solving, we get cosφ=+1 or cosφ=−12 i.e. φ=0 Or φ=120∘

Suggest Corrections
1
Join BYJU'S Learning Program
Related Videos
Energy in SHM
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program