Question

Two particles A and B are in motion. If the wavelength associated with particle A is $8\times {10}^{7}m$, calculate the wavelength associated with particle B if its momentum is $\frac{1}{4}$ of A.

• A. $32\times {10}^{-7}m$
• B. $2\times {10}^{-7}m$
• C. $4\times {10}^{-7}m$
• D. $5\times {10}^{-7}m$

Answer 1

The correct option is A $32\times {10}^{-7}m$

$\lambda =\frac{h}{p}$

$\frac{{\lambda }_1}{{\lambda }_2}=\frac{p_2}{p_1}$