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Question

Two particles A and B start from rest and move for equal time on a straight line. The particle A has an acceleration a for the first half of the total time and 2a for the second half. The particle B has an acceleration 2a for the first and a for the second half. Which particle has covered larger distance?

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Solution


From the velocity–time graph, we have:
Distance covered by A = (12×t2×at2+12×t2×at2+t2×at2)=at22
Distance covered by B = (12×at×t2+at×t2+12×at2×t2)=78at2
∴ Distance covered by A < Distance covered by B

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