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Question

Two particles are simultaneously projected in opposite direction horizontally from a given point in space where gravity g is uniform.If u1andu2 be their initial speeds, then the time t after which their velocities are mutually perpendicular is given by

A
u1u2g
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B
u21+u22g
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C
u1(u1+u2)g
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D
u2(u1+u2)g
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Solution

The correct option is C u1u2g

v1=u1^igt^j

v2=u2^igt^j

forv1v2

¯v1.¯v2=0

(u1^igt^j).(u2^igt^j)=0

u1u2+g2t2=0

g2t2=u1u2

t=u1u2g


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