Question

Two particles have equal masses of 5.0 g each and opposite charges of $+4.0\times {10}^{-5}C$ and $-4.0\times {10}^{-5}$C.
They are released from rest with a separation of 1.0 m between them find the speeds of the particles when the separation is reduced to 50 cm.

Answer 1

$q_1=q_2=4\times {10}^{-5},S=1m,m=5g=0.0005kg,f=k=14.4NSoacclna=2880m/s^{2}Now,u=0,s=50cm=0.5cm,a=2880m/s^2,v=?v^2=u^2+2as{v}^2=2\times 2880\times 0.5v=\sqrt{2280}=53.66m/s=54m/s$ for each particle