wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two particles having masses 3 kg and 6 kg are situated in a plane perpendicular to line AB at a perpendicular distance of 2 m and 4 m respectively as shown in figure. Find the moment of inertia about an axis AB parallel to AB.


A
216 kg-m2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
108 kg-m2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
300 kg-m2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
200 kg-m2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 216 kg-m2
Given,
m1=3 kg,m2=6 kg
r1=2 m;r2=4 m (perpendicular distances of m1 and m2 from axis AB)
Let us consider 3 kg is at the origin along axis AB. Then r1=0,r2=r1+r2=6 m moment of inertia of two particle system about AB is
IAB=m1r21+m2r22
=3(0)+6(6)2=216 kg-m2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon