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Standard XII

Physics

Satellites

Two particles...

Question

Two particles of mass $5 kg$ and $10 kg$ respectively are attached to the two ends of a rigid rod of length $1 m$ with negligible mass. The centre of mass of the system from the $5 kg$ particle is nearly at a distance of :

67 cm

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80 cm

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33 cm

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50 cm

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Solution

The correct option is A $67 cm$

Suppose, centre of mass is $x cm$ away from mass $5 kg$ and assume that mass $5 kg$ is at $x = 0$ .

So,
$X = \frac{m_{1} x_{1} + m_{2} x_{2}}{m_{1} + m_{2}}$

$\Rightarrow X = \frac{(5) (0) + (10) (100)}{5 + 10}$

$\Rightarrow X = \frac{1000}{15}$

$\Rightarrow X \approx 67 cm$

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Two particles of mass 5 kg and 10 kg respectively are attached to the two ends of a rigid rod of length 1 m with negligible mass. The centre of mass of the system from the 5 kg particle is nearly at a distance of :

The correct option is A 67 cm Suppose, centre of mass is x cm away from mass 5 kg and assume that mass 5 kg is at x=0. So, X=m1x1+m2x2m1+m2 ⇒X=(5)(0)+(10)(100)5+10 ⇒X=100015 ⇒X≈67 cm

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