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Question

Two particles of masses m1,m2 moving with initial velocities u1 and u2. On collision, one of the particles get excited to higher level, after absorbing energy ε . If final velocities of particles be v1 andv2 then we must have :


A

1/2 m21u21+1/2m22u22+ε =1/2 m21v21+1/2m22v22

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B

m21u1+m22u2ε = 1/2 m21v1+m22v2

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C

1/2 m1u21 + 1/2 m2u22 =1/2 m1v21 + 1/2 m2v22ε

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D

1/2 m1u21 + 1/2 m2u22 – ε = 1/2 m1v21 + 1/2 m2v22

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Solution

The correct option is D

1/2 m1u21 + 1/2 m2u22 – ε = 1/2 m1v21 + 1/2 m2v22


System's energy will be used for excitation


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