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Question

Two particles, of masses M and 2M, moving, as shown, with speeds of 10 m/s and 5 m/s, collide elastically at the origin. After the collision, they move along the indicated directions with speeds v1 and v2, respectively. The values of v1 and v2 are nearly

A
3.2 m/s and 12.6 m/s
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B
3.2 m/s and 6.3 m/s
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C
6.5 m/s and 6.3 m/s
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D
6.5 m/s and 3.2 m/s
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Solution

The correct option is C 6.5 m/s and 6.3 m/s
Given:
Speed of mass M particle =10 m/s
Speed of mass 2M particle =5 m/s

Applying conservation of linear momentum in X and Y direction for the system then

M(10cos30°)+2M(5cos45°)=2M(v1cos30°)+M(v2cos45°)

53+52=3v1+v22 ... (1)
Also

2M(5sin45°)M(10sin30°)=2Mv1sin30°Mv2sin45°

525=v1v22 ... (2)

Solving equation (1) and (2)

(3+1)v1=53+1025

v1=6.5 m/s

v2=6.3 m/s

Hence option (A) is correct.

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