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Standard XII

Physics

Phase Difference

Two particles...

Question

Two particles of medium disturbed by the wave propagation are at $x_{1} = 0 a n d x_{2} = 1 c m$ . The respective displacements (in cm) of the particles can be given by the equations: $y_{1} = 2 s i n 3 π t, y_{2} = 2 s i n (3 π t - \frac{π}{8})$ . The wave velocity is

16 cm/s

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24 cm/s

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12 cm/s

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8 cm/s

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Solution

The correct option is B
24 cm/s

$G i v e n ω = 3 π f = \frac{ω}{2 π} = 1.5 A l s o Δ x = 1.0 c m Δ ϕ = \frac{2 π}{λ} Δ x \Rightarrow \frac{π}{8} = \frac{2 π}{λ} \times 1 λ = 16 c m v = f λ = 16 \times 1.5 = 24 c m / s$

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Two particles of medium disturbed by the wave propagation are at $x_{1} = 0 a n d x_{2} = 1 c m$ . The respective displacements (in cm) of the particles can be given by the equations: $y_{1} = 2 s i n 3 π t, y_{2} = 2 s i n (3 π t - \frac{π}{8})$ . The wave velocity is

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Two particles of medium disturbed by the wave propagation are at x1=0 and x2=1 cm. The respective displacements (in cm) of the particles can be given by the equations: y1=2sin3πt,y2=2 sin(3πt−π8). The wave velocity is

The correct option is B 24 cm/s Given ω=3πf=ω2π=1.5Also Δx=1.0cmΔϕ=2πλΔx⇒π8=2πλ×1λ=16 cmv=fλ=16×1.5=24 cm/s

Two particles of medium disturbed by the wave propagation are at $x_{1} = 0 a n d x_{2} = 1 c m$ . The respective displacements (in cm) of the particles can be given by the equations: $y_{1} = 2 s i n 3 π t, y_{2} = 2 s i n (3 π t - \frac{π}{8})$ . The wave velocity is

The correct option is B
24 cm/s

$G i v e n ω = 3 π f = \frac{ω}{2 π} = 1.5 A l s o Δ x = 1.0 c m Δ ϕ = \frac{2 π}{λ} Δ x \Rightarrow \frac{π}{8} = \frac{2 π}{λ} \times 1 λ = 16 c m v = f λ = 16 \times 1.5 = 24 c m / s$