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Acceleration Due to Gravity

Two particles...

Question

Two particles,one of mass m and the other of mass 2 m, are projected horizontally towards each other from the same level above the ground with velocities 10 m/s and 5 m/s, respectively. They collide in air and stick to each other.The distance of the combined mass from point A is

40 m

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20 m

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30 m

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zero

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Solution

The correct option is A 40 m
Given,

Velocity A & B, $V_{A} = 10 m / s & V_{B} = - 5 m / s$

Distance A to B, $A B = 60 m$

Relative velocity of A with respect to B $V_{A B} = V_{A} - V_{B} = 10 - (- 5) = 15 m / s$

Time required to cover distance A to B, $t = \frac{A B}{V_{A B}} = \frac{60}{15} = 4 sec$

Hence, at 4sec they both collide and stick together

In 4 sec, distance cover by A $= V_{A} t = 10 \times 4 = 40 m$

They both collide at $40 m$ from A

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