Two periodic waves of amplitudes $a$ and $b$ pass through a region at the same time in the same direction. If $a > b$ , the difference in the maximum and minimum possible amplitudes is

a + b

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a - b

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2 a

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2 b

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Solution

The correct option is D $2 b$
Two waves pass at same time and same direction.
$\Rightarrow$ maximum amplitude is $a + b$ and minimum amplitude is $a - b$
$∴$ Difference is $a + b - (a - b) = 2 b$

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