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Standard XIII

Physics

Relative Velocity in 2D

Two person A ...

Question

Two person $A$ and $B$ start running from same initial point and in same direction along a circular path with speed of $5 km/hr$ and $2 km/hr$ respectively. If the length of circular path is $24 km$ , after what time they will meet again?

8 hr

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Solution

The correct option is A $8 hr$

Speed of $A$ w.r.t. $B = v_{A} - v_{B}$
$= (5 - 2) km/hr$
$= 3 km/hr$
To meet again, $A$ has to cover distance equal to the length of circular path with respect to $B$ .
$∴ S_{A / B} = 24 km$
$∴$ Time taken $t = \frac{S_{A / B}}{v_{A / B}} = \frac{24}{3} = 8 hr$

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Two person A and B start running from same initial point and in same direction along a circular path with speed of 5 km/hr and 2 km/hr respectively. If the length of circular path is 24 km, after what time they will meet again?

The correct option is A 8 hr Speed of A w.r.t. B=vA−vB =(5−2) km/hr =3 km/hr To meet again, A has to cover distance equal to the length of circular path with respect to B. ∴SA/B=24 km ∴ Time taken t=SA/BvA/B=243=8 hr

Two person $A$ and $B$ start running from same initial point and in same direction along a circular path with speed of $5 km/hr$ and $2 km/hr$ respectively. If the length of circular path is $24 km$ , after what time they will meet again?

The correct option is A $8 hr$

Speed of $A$ w.r.t. $B = v_{A} - v_{B}$
$= (5 - 2) km/hr$
$= 3 km/hr$
To meet again, $A$ has to cover distance equal to the length of circular path with respect to $B$ .
$∴ S_{A / B} = 24 km$
$∴$ Time taken $t = \frac{S_{A / B}}{v_{A / B}} = \frac{24}{3} = 8 hr$