Question

Two pieces of lengths $2\frac{3}{5}$ m and $3\frac{3}{10}$m are cut off from a rope 11 m long. What is the length of the remaining rope?

Answer 1

Length of pieces cut $2\frac{3}{5}$m and $3\frac{3}{10}$m.

Total length cut=$\frac{13}{5}+\frac{33}{10}$=$\frac{59}{10}$

Total length initially=$11$m

Length of the rope remaining =$11-\frac{59}{10}$= $\frac{51}{10}$m= $5\frac{1}{10}$m