Two pipes A and B can fill a tank in 15 minutes and 20 minutes respectively. Both the pipes are opened together but after 4 minutes, pipe A is turned off. What is the total time required to fill the tank?
A
10 min. 20sec.
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B
11 min. 45sec.
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C
12 min. 30 sec.
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D
14 min. 40 sec.
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Solution
The correct option is D14 min. 40 sec. Part filled in 4 minutes =4(115+120)=715. Remaining part=(1−715)=815. Part filled by B in 1 minute =120 ∴120:815::1:x x=(815×1×20)=1023min=10 min. 40 sec. ∴ The tank will be full in (4 min. +10 min. +40 sec.)=14min. 40sec.