Two plane mirrors are inclined at angle ′θ′ as shown in figure. If a ray parallel to OB strikes the other mirror at P and finally emerges parallel to OA after two reflections the θ is equal to :
A
90o
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B
60o
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C
45o
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D
30o
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Solution
The correct option is B60o ∠AOT=∠APM (correspondence because PM ∥ OB) θ=∠APM ∠APM=∠C×M (correspondence OA ∥ TC$) ∠C×M=∠CTB (correspondence XM ∥ TB$) θ=∠CTB ∠APM=∠OPT (Law of Reflection ) θ=∠OPT ∠CTB=∠PTO θ=∠PTO In △OTP θ+θ+θ=180 3θ=180 θ=60o