Two plane mirrors; $M_{1}$ and $M_{2}$ are inclined to each other at 60°. A ray parallel to the horizontal mirror $M_{2}$ strikes $M_{1}$ and after reflecting, strikes $M_{2}$ where it gets reflected again. Find the final angle of reflection after the ray strikes $M_{2}$ .

60°

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0°

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90°

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30°

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Solution

The correct option is D 30°

The incident ray that is parallel to the mirror $M_{2}$ will strike the mirror $M_{1}$ at point P at an angle of 30°.

This ray gets reflected and strikes $M_{2}$ at point S.

Since, angles PQS and QPS are $60 °$ , the angle between the ray $R_{1}$ and the surface of $M_{2}$ would be $60 °$ . (Sum of all the angles in a triangle = $180 °$ )

That means, the angle at which $R_{2}$ incidents on $M_{2}$ is $30 °$ . So, the angle of reflection would be $30 °$ .

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