Two plant cells, A and B are dividing in arithmetic and geometric manner respectively. If they complete 10 divisions, the number of daughter cells produced from A and B, respectively is

20 and 11

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11 and 1035

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20 and 20

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11 and 1024

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Solution

The correct option is D
11 and 1024

Cell A shows arithmetic growth. In arithmetic growth, following mitotic cell division only one daughter cell continues to divide, while the other differentiates and matures . The number of cells present after n divisions is n+1. So the number of daughter cells produced are = (n+1) =10+1=11.

Cell B shows geometric growth. In geometric growth, after each division, the cell count doubles and number of daughter cells produced is 2ⁿ. So the number of daughter cells produced are = $2^{n} = 2^{10} = 1024$ .

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