Question

Two plates are at potentials $-10V$ and $+30V$. If the separation between the plates is $2cm$ then the electric field between them will be

• A. 2000 V/m
• B. 1000 V/m
• C. 500 V/m
• D. 3000 V/m

Answer 1

The correct option is A 2000 V/m

Given,

$d=2cm$

$V_2-V_1=+30V-(-10)=40V$

Electric field, $E=\frac{V_2-V_1}{d}$

$E=\frac{40}{2\times {10}^{-2}}=2000V/m$

The correct option is A.