Two plates are connected by fillet welds of size $8 m m$ and subjected to a tensile force of $350 k N$ . The thickness of each plate is $12 m m$ . The yield stress and ultimate stress of steel are $250 M P a$ and $410 M P a$ respectively. As per IS 800 : 2007, the length $(l)$ required to transmit the load is ____mm. (The welding is done at site).
145

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Solution

The correct option is A 145
Given, size of weld, $s = 8 m m$ ;
Effective throat thickness $(t_{t}) = (0.7 \times 5) = (0.7 \times 0.8) = 5.6 m m$
$f_{u} = 410 M P a, f_{y} = 250 M P a, γ_{m w} = 1.5$ (at site)
Strength of weld per mm length $= (\frac{f_{u}}{\sqrt{3}}) \frac{t_{t}}{γ_{m w}}$
$= (\frac{410}{\sqrt{3}}) \frac{5.6 \times 8}{1.5}$
$= 883.73 N / m m$
$∴$ Length of weld required to transmit $350 k N$ load
$2 l + 100 = \frac{350 \times 10^{3}}{883.73}$
$2 l + 100 = 396$
$l = 148 m m$

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