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Resistance

Two platinum ...

Question

Two platinum electrodes fitted in a conductance cell are 1.5 cm apart & the cross sectional area of each electrode is $0.75 c m^{2}$ . The cell constant is

A

1.25

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B

0.25 c m

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C

2.0 c m^{- 1}

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D

0.2 c m^{- 1}

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Solution

The correct option is C $2.0 c m^{- 1}$
$C e l l c o n s t a n t = \frac{l e n g t h b e t w e e n e l e c t r o d e s}{A r e a o f e l e c t r o d e s} = \frac{1.5}{0.75}$
$= 2 c m^{- 1}$

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