Two point charges 3×10−6C and 8×10−6C repel each other by a force of 6×10−3N. If each of them is given an additional charge −6×106C, the force between them will be
A
2.4×10−3N (attractive)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2.4×10−9N (attractive)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.5×10−3N (repulsive)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1.5×10−3N (attractive)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D1.5×10−3N (attractive) F∝Q1Q2⇒F1F2=Q1Q2Q′1Q′2 =3×10−6×8×10−6(3×10−6−6×10−6)(8×10−6−6×10−6)=3×8−3×2=−41 ⇒F2=−F14=−6×10−34=−1.5×10−3N (Attractive)