You visited us 1 times! Enjoying our articles? Unlock Full Access!

Infinite Sheet

Two point cha...

Question

Two point charges of $1 μ C$ and $- 1 μ C$ are separated by a distance of $100 ˚ A$ . A point $P$ is at distance of $10 c m$ from the midpoint and on the perpendicular bisector of the line joining the two charges. The electric field at $P$ will be

9 N C^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.9 N C^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.09 N C^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

90 N C^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $0.09 N C^{- 1}$
The point lies on equatorial line of a short dipole
$∴$ $E = \frac{2 q l}{4 π ε_{0} r^{3}} = \frac{9 \times 10^{9} \times 10^{- 6} \times 10^{- 8}}{{(10^{- 1})}^{3}} = 0.09 N C^{- 1}$

Suggest Corrections

Similar questions

Q. Two charges

10 μ C

and

- 10 μ C

are placed at points

A

and

B

separated by a distance of

10 c m

.Find the electric field at a point

P

on the perpendicular bisector of

A B

at a distance of

12 c m

from its middle point

Two equal charges q of opposite sign are separated by a small distance ' $2 l$ '. The electric potential at a point on the perpendicular bisector of the line joining the two charges at a distance r is :

Q. Two point charges of

5 \times 10^{- 19} C

and

20 \times 10^{- 19} C

are separated by a distance of

2 m

. At which point on the line joining them electric field is zero?

Q. Two points charges

4 μ C

and

- 2 μ C

are separated by a distance of 1 m in air. At what point in between the charges and on the line joining the charges, is the electric potential zero?

Q. Two charged spheres A and B are charged with the charges of+10 and+20 coul. respctively and separated by a distance of 80 cm. The electric field at a point on the line joining the centres of the two sphers will be zero at a distance from sphere A-

Join BYJU'S Learning Program

Two point charges of 1 μC and −1 μC are separated by a distance of 100 ˚A. A point P is at distance of 10 cm from the midpoint and on the perpendicular bisector of the line joining the two charges. The electric field at P will be

The correct option is C 0.09NC−1The point lies on equatorial line of a short dipole∴ E=2ql4πε0r3=9×109×10−6×10−8(10−1)3=0.09NC−1

Two point charges of $1 μ C$ and $- 1 μ C$ are separated by a distance of $100 ˚ A$ . A point $P$ is at distance of $10 c m$ from the midpoint and on the perpendicular bisector of the line joining the two charges. The electric field at $P$ will be

The correct option is C $0.09 N C^{- 1}$
The point lies on equatorial line of a short dipole
$∴$ $E = \frac{2 q l}{4 π ε_{0} r^{3}} = \frac{9 \times 10^{9} \times 10^{- 6} \times 10^{- 8}}{{(10^{- 1})}^{3}} = 0.09 N C^{- 1}$