Two point charges $q_{1} = 2 μ C$ and $q_{2} = 1 μ C$ are placed at distances $b = 1 cm$ and $a = 2 cm$ from the origin of $y$ and $x$ axes as shown in figure. The electric field vector at point $P (a, b)$ will subtend an angle $(θ)$ with the $x -$ axis given by $tan θ = x$ . Find value of $x$ (Give integer value) :

2.0

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2.00

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Solution

We know that, $E \propto \frac{q}{r^{2}}$

From the above figure, $tan θ = \frac{E_{0}}{E_{0} / 2} = 2$

Accepted answer : $2$

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