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Question

Two point charges Q1 and Q2 are positioned at points 1 and 2 respectively. The field intensity to the right of the charge Q2 on the line that passes through the two charges varies according to a law that is represented schematically in the figure. The field intensity is assumed to be positive, if its direction coincides with the positive direction on the x− axis. The distance between the charges is l. Then,

A
Q1,Q2= Positive
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B
Q1,Q2= Negative
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C
Q1= Positive, Q2= Negative
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D
Q1= Negative, Q2= Positive
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Solution

The correct option is C Q1= Positive, Q2= Negative
Between x=l to x=l+a, the field intensity is negative. This means Q2 at point 2 is negative.
But for x>l+a, the field intensity is positive with maximum at x=l+b. This means Q1 is positive and due to which net electric field at x>l+a becomes positive.
Therefore, option (c) is correct.

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