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Charge

Two point cha...

Question

Two point charges $Q_{1}$ and $Q_{2}$ are positioned at points $1$ and $2$ respectively. The field intensity to the right of the charge $Q_{2}$ on the line that passes through the two charges varies according to a law that is represented schematically in the figure. The field intensity is assumed to be positive, if its direction coincides with the positive direction on the $x -$ axis. The distance between the charges is $l$ . Then,

A

Q_{1}, Q_{2} =

Positive

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B

Q_{1}, Q_{2} =

Negative

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C

Q_{1} =

Positive,

Q_{2} =

Negative

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D

Q_{1} =

Negative,

Q_{2} =

Positive

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Solution

The correct option is C $Q_{1} =$ Positive, $Q_{2} =$ Negative
Between $x = l$ to $x = l + a$ , the field intensity is negative. This means $Q_{2}$ at point $2$ is negative.
But for $x > l + a$ , the field intensity is positive with maximum at $x = l + b$ . This means $Q_{1}$ is positive and due to which net electric field at $x > l + a$ becomes positive.
Therefore, option (c) is correct.

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