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Question

Two point charges Q1 and Q2 exerts force F on each other, when kept at certain distance apart. If the charge on each particle is halved and the distance between them is doubled, then the new force between the two particles would be

A
F2
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B
F4
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C
F8
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D
F16
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Solution

The correct option is D F16
From Coulomb's law:

F=kQ1Q2r2 (1)

Since
Q1=Q12, Q2=Q22 and r=2r

From Eq. (1), we get

F=k(Q12)(Q22)(2r)2

F=kQ1Q216 r2 ......(2)

from Eq.(1) and Eq.(2), we get

F=F16

Hence, option (d) is the correct answer.

Why this question ?It intends to test your understanding of direct andinverse proportionality of parameters in Coulomb's law.

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