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Question

Two point masses m1 and m2 are joined by a weightless rod of length r. Calculate the moment of inertia of the system about an axis passing through its centre of mass and perpendicular to the rod.

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Solution

r1=(m2m1+m2)r
r2=(m1m1+m2)r
Ic=m1r21+m2r22
l=μr2 where μ=m1m2m1+m2 is called the reduced mass of two masses.
233892_215984_ans_0576cde5a1c34ac6ac74da17cafbc5a4.png

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